If a-bx - a-bx - b-cx - b-cx - c-dx - c-dx x- 0- then show that a-b-c and d are in G-P-

Using componendo dividendo, nbsp; a+bx / a bx = b+cx / b cx = c+dx / c dx ⇒ nbsp; 2a / 2bx = 2b / 2cx = 2c / 2dx ⇒a/b=b/c=c/d⇒ a,b,c,d∈G.P. ...

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Integration of Piecewise Continuous Functions

If a+bx / a...

Question

If $\frac{a + b x}{a - b x} = \frac{b + c x}{b - c x} = \frac{c + d x}{c - d x} (x \neq 0) .$ , then show that $a, b, c$ and $d$ are in G.P.

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If $\frac{a + b x}{a - b x} = \frac{b + c x}{b - c x} = \frac{c + d x}{c - d x} (x \neq 0)$ , then show that a, b, c and d are in G.P.

\frac{a + b x}{a - b x} = \frac{b + c x}{b - c x} = \frac{c + d x}{c - d x} (x \neq 0)

a, b, c

d

G . P .

\frac{a - b x}{a - b x} = \frac{b + c x}{b - c x} = \frac{c + d x}{c - d x} (x \neq 0)

a, b, c, d

\frac{a + b x}{a - b x} = \frac{b + c x}{b - c x} = \frac{c + d x}{c - d x}, (x \neq 0)

a, b, c

d

\frac{a + b x}{a - b x} = \frac{b + c x}{b - c x} = \frac{c + d x}{c - d x} (x \neq 0),

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