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Question

If an+bnan1+bn1 is the A.M. between a, b then find the value of n.
OR
If there are (2n+1) terms in A.P., then prove that the ratio of the sum of the odd terms and the even terms is (n+1):n.

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Solution

Let a,a+d,a+2d...a+(2x+1)Re2 series
The odd terms a, a+2d, a+4d
first term = a
common diff = 2d
No. of term = x+1
Sum of odd term =(n+1)2(2a+(n+11)2d)
=(n+1)(a+nd)
The serises of even term..
a+d, a+3d, a+5d...
first term =a+d
No. of terms =x
common diff = 2d
Sum of even terms =n2[2(a+d)+(n1)2d]
=h2[2a+2d+2nd2d]
=h[a+nd]
5odd5even=(n+1)(a+nd)n(a+nd)=(n+1):h

1061276_1069640_ans_5e280e0f02634f7c89bc65a4cf2e74ef.png

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