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Byju's Answer
Standard X
Mathematics
Sum of n Terms
If a n + b ...
Question
If
a
n
+
b
n
a
n
−
1
+
b
n
−
1
is the A.M. between a, b then find the value of n.
OR
If there are
(
2
n
+
1
)
terms in A.P., then prove that the ratio of the sum of the odd terms and the even terms is
(
n
+
1
)
:
n
.
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Solution
Let
a
,
a
+
d
,
a
+
2
d
.
.
.
a
+
(
2
x
+
1
)
→
R
e
2
series
The odd terms a, a+2d, a+4d
first term = a
common diff = 2d
No. of term = x+1
Sum of odd term
=
(
n
+
1
)
2
(
2
a
+
(
n
+
1
−
1
)
2
d
)
=
(
n
+
1
)
(
a
+
n
d
)
The serises of even term..
a+d, a+3d, a+5d...
first term =a+d
No. of terms =x
common diff = 2d
Sum of even terms =
n
2
[
2
(
a
+
d
)
+
(
n
−
1
)
2
d
]
=
h
2
[
2
a
+
2
d
+
2
n
d
−
2
d
]
=
h
[
a
+
n
d
]
5
o
d
d
5
e
v
e
n
=
(
n
+
1
)
(
a
+
n
d
)
n
(
a
+
n
d
)
=
(
n
+
1
)
:
h
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0
Similar questions
Q.
If there are
2
n
+
1
terms in A.P., then prove that the ratio of the sum of odd terms and even terms is
(
n
+
1
)
:
n
Q.
If there are (2n+1) terms in AP, then prove that the ratio of the sum of odd terms and the sum of even terms is (n+1) : n.
Q.
If there are
(
2
n
+
1
)
terms in an AP, then show that :
S
u
m
o
f
o
d
d
t
e
r
m
s
S
u
m
o
f
e
v
e
n
t
e
r
m
s
=
n
+
1
n
.
Q.
If
S
be the sum of
(
2
n
+
1
)
terms of an A.P and
S
1
be the sum of its odd terms, then prove that
S
:
S
1
=
(
2
n
+
1
)
:
(
n
+
1
)
Q.
If
S
1
be the sum
of (2n + 1) terms of an A.P. and
S
2
be the sum of its odd terms, then prove that
S
1
:
S
2
=
(
2
n
+
1
)
:
(
n
+
1
)
.
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