If ax-b-3x-42 -1-3x-4-3-3x-42 then a-b-

The correct option is B 4 ax+b/(3x+4)^2 =1/3x+4 3/(3x+4)^2 Cross multiplying, ⇒ ax+b=(3x+4) 3 Now put x=1 both sides, ⇒ a+b= 7 3=4 Hence 'B' ...

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Byju's Answer

Standard XII

Mathematics

Integration by Partial Fractions

If ax+b/3x+...

Question

If $\frac{a x + b}{(3 x + 4)^{2}} = \frac{1}{3 x + 4} - \frac{3}{(3 x + 4)^{2}}$
then $a + b =$

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Solution

The correct option is B 4
$\frac{a x + b}{(3 x + 4)^{2}} = \frac{1}{3 x + 4} - \frac{3}{(3 x + 4)^{2}}$
Cross multiplying,
$\Rightarrow a x + b = (3 x + 4) - 3$
Now put $x = 1$ both sides,
$\Rightarrow a + b = 7 - 3 = 4$
Hence 'B' is correct choice.

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Similar questions

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If ax+b(3x+4)2=13x+4−3(3x+4)2 then a+b=

The correct option is B 4ax+b(3x+4)2=13x+4−3(3x+4)2Cross multiplying,⇒ax+b=(3x+4)−3Now put x=1 both sides,⇒a+b=7−3=4Hence 'B' is correct choice.

If $\frac{a x + b}{(3 x + 4)^{2}} = \frac{1}{3 x + 4} - \frac{3}{(3 x + 4)^{2}}$
then $a + b =$

The correct option is B 4
$\frac{a x + b}{(3 x + 4)^{2}} = \frac{1}{3 x + 4} - \frac{3}{(3 x + 4)^{2}}$
Cross multiplying,
$\Rightarrow a x + b = (3 x + 4) - 3$
Now put $x = 1$ both sides,
$\Rightarrow a + b = 7 - 3 = 4$
Hence 'B' is correct choice.