Question

If $\frac{\cos \theta -\sin \theta }{\cos \theta +\sin \theta }=\frac{1-\sqrt{3}}{1+\sqrt{3}}$ then $\theta$ is

• A. ${30}^{\circ }$
• B. ${45}^{\circ }$
• C. ${60}^{\circ }$
• D. ${90}^{\circ }$

Answer 1

Answer: (C)

${60}^{\circ }$

$\frac{\cos \theta -\sin \theta }{\cos \theta +\sin \theta }=\frac{1-\sqrt{3}}{1+\sqrt{3}}$
$\frac{1-\tan \theta }{1+\tan \theta }=\frac{1-\sqrt{3}}{1+\sqrt{3}}$
By comparison
$\theta ={60}^{\circ }$