Question

If $\frac{\log 128}{\log 32}=x$, then the value of $x$ will be

• A. $\frac{5}{7}$
• B. $\frac{7}{5}$
• C. $\frac{8}{5}$
• D. $\frac{5}{8}$

Answer 1

The correct option is B $\frac{7}{5}$

Given, $\frac{\log 128}{\log 32}=x$

$\Rightarrow \frac{\log 2^7}{\log 2^5}=x$

$\Rightarrow \frac{7\log 2}{5\log 2}=x$ (Using $\log a^b=b\log a$)

$\therefore x=\frac{7}{5}$.