Question

If $\frac{\log 81}{\log 27}=x$ and $x$ is expressed as $1\frac{1}{m}$, then $m$ is equal to

• A. $2$
• B. $1$
• C. $0$
• D. $3$

Answer 1

The correct option is D $3$

$\frac{\log 81}{\log 27}=x$
$\Rightarrow x=\frac{\log 3^4}{\log 3^3}=\frac{4\log 3}{3\log 3}=\frac{4}{3}=1\frac{1}{3}$

$\therefore m=3$