If x4-1-x-1x-2-Ax2-Bx-C-2-x-1-17-x-2- then C-

The correct option is D 7 In the equation x^4+1/(x 1)(x 2)=Ax^2+Bx+C 2/x 1+17/x 2 put x=0 12=C+24 172 c=7 the value of c=7 ...

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Combination

If x4+1/x-1...

Question

If $\frac{x^{4} + 1}{(x - 1) (x - 2)} = A x^{2} + B x + C - \frac{2}{x - 1} + \frac{17}{x - 2}$ , then $C =$

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Similar questions

$\int \frac{x^{2} + 1}{x^{4} + 1} d x$ will be equal to which of the following

\frac{x^{2} + 5}{(x^{2} + 1) (x - 2)} = \frac{A}{x - 2} + \frac{B x + C}{x^{2} + 1}

A + B + C =

\frac{7 x^{3} + 3 x^{2} - x + 1}{x + 1} = (a x^{2} + b x + c) - \frac{2}{x + 1}

a =

\frac{x^{2} + 5 x + 1}{(x + 1) (x + 2) (x + 3)} = \frac{A}{x + 1} + \frac{B}{(x + 1) (x + 2)} + \frac{C}{(x + 1) (x + 2) (x + 3)}

x^{3} - 3 x^{2} + 3 x - 7 = (x + 1) (a x^{2} + b x + c)

a + b + c

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