Question

If $\frac{p}{q}=\frac{6}{5}$ then find the value of the ratio:$\frac{3p+4q}{3p-4q}$.

Mark TRUE if the value is $\frac{19}{1}$ otherwise mark FALSE.

• A. True
• B. False

Answer 1

The correct option is B False

Given that,

$\frac{p}{q}=\frac{6}{5}$

$\therefore p=6xandq=5x$

$\frac{3p+4q}{3p-4q}=\frac{3\times 6x+4\times 5x}{3\times 6x-4\times 5x}$

$=\frac{18x+20x}{18x-20x}=\frac{38}{-2}$

$=\frac{19}{-1}$

$=\frac{-19}{1}$

Hence the answer is FALSE