If sin 2-sin 3-sin 4-cos 2-cos 3-cos 4-tan k- is an identity then the value of k is equal to

The correct option is B 3 sin2α+sin4α sin3αcos2α+cos4α cos3α =2sin3α.cosα sin3α2cos3α.cosα cos3α =sin3α(2cosα 1)cos3α(2cosα 1) =tan3α ...

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Sum of Trigonometric Ratios in Terms of Their Product

If sin 2α-s...

Question

If $\frac{s i n 2 α - s i n 3 α + s i n 4 α}{c o s 2 α - c o s 3 α + c o s 4 α} = t a n k α$ is an identity then the value of k is equal to

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\frac{s i n^{4} α - c o s^{4} α + c o s^{2} α}{2 (1 - c o s α)} = c o s^{2} \frac{α}{2} .

{sin}^{16} α = \frac{1}{5}

\frac{1}{{cos}^{2} α} + \frac{1}{1 + {sin}^{2} α} + \frac{2}{1 + {sin}^{4} α} + \frac{4}{1 + {sin}^{8} α}

tan α = 2

\frac{sin α}{{sin}^{3} α + {cos}^{3} α}

α = 2

α \in (π, \frac{3 π}{2})

\frac{cos α}{{sin}^{3} α + {cos}^{3} α}

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