If tan 2-tan -1-tan - tan 2 -0- So find the general value of -

The correct option is B nπ/3 ; n ∈ l nbsp; tan 2θ +tan θ nbsp;/ 1 tan θ tan 2 θ nbsp; =0⇒tan 3θ nbsp; =0 nbsp;⇒ 3θ =nπ⇒θ = nπ nbsp;/ 3 ...

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Byju's Answer

Standard XII

Mathematics

Polar Representation of a Complex Number

If tan 2θ+t...

Question

If $\frac{t a n 2 θ + t a n θ}{1 - t a n θ t a n 2 θ} = 0$ . So find the general value of $θ$

n π; n \in l

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\frac{n π}{3}; n \in l

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\frac{n π}{4}

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\frac{n π}{6}; n \in l

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Solution

The correct option is B $\frac{n π}{3}; n \in l$
$\frac{t a n 2 θ + t a n θ}{1 - t a n θ t a n 2 θ} = 0 \Rightarrow tan 3 θ = 0$
$\Rightarrow 3 θ = n π \Rightarrow θ = \frac{n π}{3}$

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Similar questions

Consider the system of linear equations in x, y and z ;
(sin 3 $θ$ ) x - y + z = 0 ......(i)
(cos 2 $θ$ )x + 4y + 3z = 0 ......(ii)
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The value of $θ$ for which the system has nontrivial solution is

Which of the following statements are correct?

1 . if sin θ = sin α ⇒ θ = nπ + $(- 1)^{n}$ α where α ∈ [ - $\frac{π}{2}$ , $\frac{π}{2}$ ] n ∈ I

2 . if cos θ = cos α ⇒ 2nπ±α where α ∈ [0,π] n ∈ I

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Q. The general values of

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satisfying the equation

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(n \in Z)

Q. The general solution(s) of

θ

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can be (where

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If tan2θ+tanθ1−tanθtan2θ=0. So find the general value of θ

The correct option is B nπ3;n∈ltan2θ+tanθ1−tanθtan2θ=0⇒tan3θ=0⇒3θ=nπ⇒θ=nπ3

If $\frac{t a n 2 θ + t a n θ}{1 - t a n θ t a n 2 θ} = 0$ . So find the general value of $θ$

The correct option is B $\frac{n π}{3}; n \in l$
$\frac{t a n 2 θ + t a n θ}{1 - t a n θ t a n 2 θ} = 0 \Rightarrow tan 3 θ = 0$
$\Rightarrow 3 θ = n π \Rightarrow θ = \frac{n π}{3}$