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Question

If x1+x2....+x2020=M then the value of 20i=1xiM20 is

A
19M20
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B
1
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C
0
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D
120
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Solution

The correct option is C 0

Consider given the expression,

x1+x2+.......x2020

Let,x1+x2+.......x2020=M

Now,

20i=1xiM20=20i=1(x1+x2+.......x2020)M20=20i=1MM20=0


Hence, this is the answer.

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