If x1+x2....+x2020=M then the value of 20∑i=1xi−M20 is
Consider given the expression,
⇒x1+x2+.......x2020
Let,x1+x2+.......x2020=M
Now,
20∑i=1xi−M20=20∑i=1(x1+x2+.......x2020)−M20=20∑i=1M−M20=0