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B
4C+1
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C
3C
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D
2C
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Solution
The correct option is C2C Given, x2+x+1(x+1)2=A+B(x+1)+C(x+1)2 x2+x+1(x+1)2=A(x+1)2+B(x+1)+C(x+1)2 x2+x+1=A(x+1)2+B(x+1)+C Let us put x=−2 3−c=A−B A−B=2 and f(−1)=c=1 So A−B=2C