If x-2-x2-4 - rx-x3-8- then rx is-

The correct option is B x^2 2x +4 x 2/x^2 4 = r(x)/x^3 + 8 ∴ r(x) = (x 2)(x^3+8)/x^2 4 = (x 2)(x+2)(x^2 2x+4)/(x 2)(x+2) = x^2 2x+4 ...

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Addition of Rational Expressions

If x-2/x2-4...

Question

If $\frac{x - 2}{x^{2} - 4} = \frac{r (x)}{x^{3} + 8}$ , then $r (x)$ is:

x^{2} - 2 x + 4

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x^{2} + 2 x + 4

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x^{2} - 2 x - 4

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x^{2} + 2 x - 4

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Solution

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Similar questions

p (x) = x^{2} - 4, q (x) = x^{3} - 8, r (x) = (x + 2)

s (x) = (x^{2} + 2 x + 4)

\frac{x^{2} - 7 x + 10}{x^{2} - 5 x - 14} \times \frac{x^{3} + 8}{x^{3} - 8} \times \frac{x^{2} + 2 x + 4}{x^{2} - 2 x + 4} \times \frac{x - 7}{x - 5} = ?

| | 2 x - x^{2} + 8 | - | x^{2} + 5 | | = | 2 x + 13 |

x

y = \frac{x^{2} - 2 x + 4}{x^{2} + 2 x + 4}

x

\frac{x^{2} - x - 1}{x^{3} - 8} = \frac{A}{x - 2} + \frac{B x + C}{x^{2} + 2 x + 4} \Rightarrow A + B =

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