If I - -1-x2log x2 - a2 dx- then I equals

The correct option is B 1/xlog (x^2 + a^2) + 2/atan^ 1 ( x/a ) + C I=∫ nbsp; 1 x^ 2 log nbsp;( x^ 2 +a^ 2 ) dx = 1 x log nbsp;( x^ 2 + ...

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Functions

If I = ∫1/x...

Question

If $I = \int \frac{1}{x^{2}} log (x^{2} + a^{2}) d x$ , then I equals

- \frac{1}{x} log (x^{2} + a^{2}) + 2 {tan}^{- 1} (\frac{x}{a}) + C

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- \frac{1}{x} log (x^{2} + a^{2}) + \frac{2}{a} {tan}^{- 1} (\frac{x}{a}) + C

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- \frac{1}{x} log (x^{2} + a^{2}) + \frac{2}{a} {cot}^{- 1} (\frac{x}{a}) + C

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none of these

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