If In=∫π/40tannx×sec2xdx, then I1,I2,I3, .......are in
A
A.P.
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B
G.P.
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C
H.P.
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D
none
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Solution
The correct option is D H.P. In=∫π/40tannxsec2xdx Let, t=tanx⇒sec2xdx=dt Therefore, In=∫10tndt=(tn+1)10=1n Therefore, I1,I2,I3⋯ are 12,13,14,⋯ which are in H.P Ans: C