If $\int_{0}^{1} (\frac{1}{x}) d x = λ$ then $λ = ?$

1

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\frac{1}{2}

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log 2

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log π

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Solution

The correct option is C $log 2$
$\int_{1}^{2} \frac{1}{x} d x {log x |}_{1}^{2} log 2 - log 1 = log 2$

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