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Question

If e3xsin7x dx=e3xa[bsincx+dcoscx]+C, then the value of a+b+c+d is
(where C is constant of integration)

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Solution

We know
eaxsinbx=eaxa2+b2[asinbxbcosbx]+Ce3xsin7x dx=e3x32+72[3sin7x7cos7x]+Ca=49+9=58, b=3, c=7, d=7
Hence,
a+b+c+d=61

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