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Question

If 1x+x5dx=f(x)+c, then x4x+x5dx is equal to

A
log|x|+f(x)+c
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B
log|x|f(x)+c
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C
xf(x)+c
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D
None of these
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Solution

The correct option is C log|x|f(x)+c
Let I1=1x+x5dx and I2=x4x+x5dx

I1+I2=(1x+x5+x4x+x5)dx=1+x4x+x5dx

=dxx=log|x|+c

As I1=f(x)+c

I2=log|x|f(x)+c

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