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Question

If dxx+x7 = p(x) then, x6x+x7dx is

A
ln|x| p(x) + c
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B
ln|x| + p(x) + c
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C
xp(x)+c
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D
x+p(x)+c
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Solution

The correct option is A ln|x| p(x) + c
dxx+x7=p(x)
x6(x+x7)dx
=(x7)x(x+x7)dx
=(x+x7x)x(x+x7)dx
=x+x7x(x+x7)dx
=xx(x+x7)dx
=ln|x|dxx+x7
=ln|x|p(x)+c.

1185272_1207889_ans_27fa92241cb345c8bec7ccbe07ee7969.jpg

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