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Question

If 10tan1xcot1(1x+x2)dx equals k, then the value of 1k is

A
3
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B
2
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C
7
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D
13
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Solution

The correct option is B 2
k=10tan1xcot1(1x+x2)dx (1)
k=10tan1xcot1((1x)2+x)dx
Applying baf(x)dx=baf(a+bx)dx,
k=10tan1(1x)cot1((11+x)2+(1x))dx
k=10tan1(1x)cot1(x2+1x)dx (2)

From (1)+(2),
2k=10tan1(1x)+tan1(x)cot1(x2+1x)dx
2k=10tan1(x+1x1+x(1x))cot1(x2+1x)dx
2k=10tan1(1x2+1x)cot1(x2+1x)dx
2k=101dx
k=12
1k=2

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