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Question

If 41f(x)dx=4 and 42(3f(x))dx=7, then which of the following is/are true:

A
42f(x)dx=1
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B
42f(x)dx=1
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C
21f(x)dx=5
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D
21f(x)dx=5
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Solution

The correct option is C 21f(x)dx=5
We have
42(3f(x))dx=7642f(x) dx=742f(x)dx=1
Now,
41f(x)dx=44=21f(x)dx+42f(x)dx21f(x)dx1=421f(x)dx=5

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