wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x5e4x3dx=148e4x3f(x)+C, where C is a constant of integration, then f(x) is equal to :

A
2x31
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4x31
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4x3+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2x3+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 4x31
Given,
x5e4x3dx=148e4x3f(x)+C
Put x3=t 3x2dx=dt
x3e4x3x2dx=13te4tdt
=13[te4t4e4t4dt]
=e4t48[4t+1]+C
=e4x348[4x3+1]+C
f(x)=14x3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Parts
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon