If l12-m12-n12-1- etc and l1l2-m1m2-n1n2-0 and - - l1 m1 n1 l2 m2 n2 l3 m3 n3 then

The correct option is C | Δ | =1 We have #160; #160; Δ^2=Δ·Δ #160; = #160;l_1 amp;m_1 #160; amp;n_1 #160;l_2 amp; m_2 amp;n_2 ...

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If l12+m12+...

Question

If $l_{1}^{2} + m_{1}^{2} + n_{1}^{2} = 1, e t c a n d l_{1} l_{2} + m_{1} m_{2} + n_{1} n_{2} = 0$ and
$Δ = ∣ ∣ ∣ ∣ \begin{matrix} l_{1} & m_{1} & n_{1} l_{2} & m_{2} & n_{2} l_{3} & m_{3} & n_{3} \end{matrix} ∣ ∣ ∣ ∣$ then

| Δ | = 3

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| Δ | = 2

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| Δ | = 1

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| Δ | = 0

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