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Standard XII

Chemistry

Kohlrausch Law

If Λm0 for ...

Question

If $Λ_{m}^{0}$ for $N a C l, H C l$ and $C H_{3} C O O H$ are $110, 100$ and $390 m o l e^{- 1}$ respectively. Determine the value of $Λ_{m}^{0}$ for $C H_{3} C O O N a$ ?

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Solution

Apply Kohlrausch law of independent migration of ions.
$Λ_{m}^{0} (C H_{3} C O O N a) = Λ_{m}^{0} (C H_{3} C O O H) + Λ_{m}^{0} (N a C l) - Λ_{m}^{0} (H C l)$
$Λ_{m}^{0} (C H_{3} C O O N a) = 390 + 110 - 100$
$Λ_{m}^{0} (C H_{3} C O O N a) = 400 S m^{2} / m o l$

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Similar questions

Λ^{O}

for

N a C l, H C l

and

{C H}_{3} C O O N a

are

126.0, 426.0

and

91.0 S {c m}^{2} {m o l}^{- 1}

respectively. Calculate

Λ^{O}

for

{C H}_{3} C O O H

Q. Calculate

α

C H_{3} C O O H

Λ_{m}^{\infty}

for

H C l, N a C l

C H_{3} C O O N a

are

426, 126, 91

C m^{1}

, respectively, and

Λ_{m} = 14.4 S c m^{2} m o l^{- 1}

0.015

M concentration.

Q. Molar conductives

(Λ_{m}^{o})

at infinite dilution of

N a C l, H C l

and

{C H}_{3} C O O N a

are

126.4, 425.9

and

91.0 S {c m}^{2} {m o l}^{- 1}

respectively.

Λ_{m}^{o}

for

{C H}_{3} C O O H

will be:

Q. Molar conductivities at infinite dilution of

N a C l

H C l

and

C H_{3} C O O N a

are 126.4, 425.9 and 91.0

S c m^{2} m o l^{- 1}

respectively. Molar conductivity for

C H_{3} C O O H

will be:

The molar conductances of HCl, NaCl and $C H_{3} C O O N a$ are 426, 126 91 $Ω^{- 1} c m^{2} m o l^{- 1}$ respectively. The molar conductances of $C H_{3} C O O H$ is :

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If Λ0m for NaCl,HCl and CH3COOH are 110,100 and 390 mole−1 respectively. Determine the value of Λ0m for CH3COONa?

Apply Kohlrausch law of independent migration of ions.Λ0m(CH3COONa)=Λ0m(CH3COOH)+Λ0m(NaCl)−Λ0m(HCl)Λ0m(CH3COONa)=390+110−100Λ0m(CH3COONa)=400Sm2/mol

If $Λ_{m}^{0}$ for $N a C l, H C l$ and $C H_{3} C O O H$ are $110, 100$ and $390 m o l e^{- 1}$ respectively. Determine the value of $Λ_{m}^{0}$ for $C H_{3} C O O N a$ ?

Apply Kohlrausch law of independent migration of ions.
$Λ_{m}^{0} (C H_{3} C O O N a) = Λ_{m}^{0} (C H_{3} C O O H) + Λ_{m}^{0} (N a C l) - Λ_{m}^{0} (H C l)$
$Λ_{m}^{0} (C H_{3} C O O N a) = 390 + 110 - 100$
$Λ_{m}^{0} (C H_{3} C O O N a) = 400 S m^{2} / m o l$