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Question

If (1+sinx)(1+siny)(1+sinz)=(1sinx)(1siny)(1sinz)=k then k has the value

A
±cosxcosycosz
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B
±sinxsinysinz
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C
±3sinxsinysinz
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D
None of these
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Solution

The correct option is A ±cosxcosycosz
Multiply both sides by (1+sinx)(1+siny)(1+sinz)
(1+sinx)(1+siny)(1+sinz)
=(1sin2x)(1sin2y)(1sin2z)
=cos2xcos2ycos2z
(1+sinx)(1+siny)(1+sinz)
=±cosxcosycosz

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