If 1 - tan- 1 - tan 4- - 2- - - 0- -16 then - is equal to

The correct option is B π/20 (1 + tanα) ( 1+ tan4α) = 2 ⇒ 1 + tanα. tan4α + tanα + tan4α = 2 ⇒ #160; tanα + tan4α = 1 tanα. tan4α ...

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Sin(A+B)Sin(A-B)

If 1 + tanα...

Question

If $(1 + tan α) (1 + tan 4 α) = 2$ , $α ϵ (0, π / 16)$ then $α$ is equal to

\frac{π}{20}

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\frac{π}{30}

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\frac{π}{40}

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\frac{π}{60}

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