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Question

If (1+x)n=C0+C1x+C2x2+...+Cnxn, then C0−C1+C2−C3+...+(−1)n.Cn is equal to:

A
3n
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B
2n
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C
1
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D
0
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Solution

The correct option is C 0
Given,
(1+x)n=C0+C1x+C2x2+....+Cnxn
Put x=1, we get
C0C1+C2...+(1)n.Cn=0

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