If 1-x-x2-xn n -a0-a1x-a2x2- -ampxmp then a1-2a2-3a3- -npanp-

The correct option is D np/2 ( p+1 )^n #10;( 1+x+ x ^ 2 +...+ x ^ p ) #160;^ n = a _ 0 + a #10;_ 1 x+...+ a _ pn x ^ pn #10; #10;Differen ...

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Combination

If 1+x+x2+·...

Question

If ${(1 + x + x^{2} + \cdot \cdot + x^{n})}^{n}$ $= a_{0} + a_{1} x + a_{2} x^{2} + \cdot \cdot \cdot + a_{m p} x^{m p}$ then $a_{1} + 2 a_{2} + 3 a_{3} + \cdot \cdot \cdot + n p a_{n p}$ =_______

\frac{n p}{4} {(p + 1)}^{n}

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\frac{n p}{4} {(p + 3)}^{n}

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\frac{n p}{2} {(p + 3)}^{n}

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\frac{n p}{2} {(p + 1)}^{n}

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Similar questions

(1 + x + x^{2} + . . . . . + x^{p})^{n} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . . a_{n p} x^{n p}

(1) a_{0} + a_{1} + a_{2} + . . . . . + a_{n p} = (p + 1)^{n}

(2) a_{1} + 2 a_{2} + 3 a_{3} + . . . . + n p . a_{n p} = \frac{1}{2} n p (p + 1)^{n}

lim n \to \infty \frac{1^{p} + 2^{p} + . . . + n^{p}}{n^{p + 1}}

{lim}_{n \to \infty} \frac{1^{p} + 2^{p} + 3^{p} + . . . + n^{p}}{n^{p + 1}}

{lim}_{n \to \infty} \frac{1^{P} + 2^{P} + 3^{P} + . . . . . . . + n^{P}}{n^{P + 1}}

l i m n \to \infty \frac{1^{P} + 2^{P} + 3^{P} + . . . . + n^{P}}{n^{P + 1}}

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