If - a b-c a-b-c - 0 then find the value of a- b-c - a-b-c

The correct option is B 0 a.{ ( b+c )× ( a+b+c ) } = a.{ ( b+c )× a+0 }= a.{ b× a+c× a } = [ a nbsp; nbsp; b nbsp; nbsp; a ]+ [ a ...

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Cartesian Product

If [ a b+c ...

Question

If $[a b + c a + b + c] = 0$ then find the value of $a . {(b + c) \times (a + b + c)}$

-1

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None of these

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a + b + c = 0

\frac{(b + c)^{2}}{b c} + \frac{(c + a)^{2}}{c a} + \frac{(a + b)^{2}}{a b}

If $a + b + c = 0$ then find value of $\frac{a^{2}}{b c} + \frac{b^{2}}{a c} + \frac{c^{2}}{a b}$

> 0

= 8

\frac{a b}{c} + \frac{b c}{a} + \frac{c a}{b}

a + b + c = 6

a b + b c + c a = 11

b c (b + c) + c a (c + a) + a b (a + b) + 3 a b c

(x^{a})^{a^{2} - b c} . (x^{b})^{b^{2} - c a} . (x^{c} c^{2 - a b})

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