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Question

If limx23x2+ax+a+3x2+x2=L. then L+a will be equal to

A
13
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B
14
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C
15
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D
None
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Solution

The correct option is C 14
limx23x2+ax+a+3x2+x2 for limit to exist 3(2)2+a(2)+a+3=0a=15
L=limx26x+152x+1=1
L+a=151=14

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