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Question

If log102=a and log103=b, then log318 can be expressed as

A
2a
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B
25a
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C
2+5a
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D
2+a
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Solution

The correct option is D 25a
Let, x=log318 = log258 = log5223
x=log52log23 (logab=loga logb)
x=2log53log2 (logab=bloga)
x=2(log10log2)3log2
x=22a3a (log10=1)
x=25a

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