1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Fundamental Laws of Logarithms
If log a+πl...
Question
If
log
(
a
+
π
)
log
2
(
√
4
x
+
1
+
√
4
x
)
=
0
,
x
ϵ
R
,
then
64
x
is equal to
A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
C
9
log
2
(
√
4
x
+
1
+
√
4
x
)
=
1
⇒
√
4
x
+
1
+
√
4
x
=
2
1
=
2
Squaring both sides, we get
4
x
+
1
+
4
x
+
2
√
4
x
(
4
x
+
1
)
=
4
⇒
8
x
−
3
+
2
√
4
x
(
4
x
+
1
)
=
0
⇒
2
√
4
x
(
4
x
+
1
)
=
3
−
8
x
Squaring both sides:
4
(
4
x
(
4
x
+
1
)
)
=
9
−
48
x
+
64
x
2
⇒
4
(
16
x
2
+
4
x
)
=
64
x
2
−
48
x
+
9
⇒
64
x
2
+
16
x
=
64
x
2
−
48
x
+
9
⇒
64
x
=
9
Suggest Corrections
0
Similar questions
Q.
If
log
(
e
+
π
)
log
2
(
√
4
x
+
1
+
√
4
x
)
=
0
,
x
ϵ
R
then
64
x
is equal to:
Q.
If
(
9
4
)
x
+
y
=
(
3
2
)
16
and
(
49
64
)
x
−
2
y
=
(
7
8
)
4
, then
x
y
=
Q.
If 4x - 5z = 16 and xz = 12,
64
x
2
−
125
z
3
=
Q.
Evaluate:
(
3
−
2
x
)
(
3
+
2
x
)
(
9
+
4
x
2
)
is equal to
81
−
16
x
4
.
If true then enter
1
and if false then enter
0
.
Q.
If
√
x
−
1
−
√
x
+
1
+
1
=
0
, then
4
x
is equal to ____.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Fundamental Laws of Logarithms
MATHEMATICS
Watch in App
Explore more
Fundamental Laws of Logarithms
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app