If log1√2sinx≥0, x∈[0,4π], then the number of values of x which are integral multiples of π4 is/are
A
6
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B
12
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C
3
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D
none of these
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Solution
The correct option is A6 log1√2sinx≥0, where x∈[0,4π] Above equation is valid when sinx>0 ⇒x∈(0,π)∪(2π,3π) log1√2sinx≥0 ⇒sinx≤1 For, x∈(0,π)∪(2π,3π) Values of x which are integral multiples of π4 are {π4,2π4,3π4,9π4,10π4,11π4} Ans: A