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Question

If logta,at/2,logbt be in G.P., then t=

A
logb(logb)loga(logb)
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B
loga(loga)loga(logb)
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C
logb(loga)loga(logb)
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D
loga(loga)logb(logb)
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Solution

The correct option is C loga(loga)loga(logb)
As logta,at/2,logbt are in G.P

(at2)2=logta.logbt=logba=logalogb

at=logalogb

t=loga(logba)=loga(logab)=loga(loga)loga(logb)

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