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Question

If logx=2m3n and logy=3n2m, then the value of log(x3÷y2) in terms of m and n is

A
10m+15n
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B
10m15n
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C
15m10n
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D
15m+10n
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Solution

The correct option is D 10m15n
logx=2m3nlogy=3n2mlog(x3y2)=logx3logy2=3logx2logy=3(2m3n)2(3n2m)=6m9n6n+4m=10m15n

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