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Question

If logx:logy:logz=(y−z):(z−x):(x−y), then which of the following condition is true?

A
xy.yz.zx=1
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B
xx.yy.zz=1
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C
xx.yy.zz.=1
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D
none of these
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Solution

The correct option is B xx.yy.zz=1
Let logxyz=logyzx=logzyz=k

Now,
xlogx+ylogy+zlogz=k[x(yz)+y(zx)+z(yz)]

logxx+logyy+logzz=0

logxxyyzz=0

xxyyzz=1

Thus the correct answer is option B

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