If $log x = n$ then 2n is equal to

log (x^{2})

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{(log x)}^{2}

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log (x + 2)

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log 2 x

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Solution

The correct option is A $log (x^{2})$
Given , $log x = n$
We know that $log x^{2} = 2 log x$
$\Rightarrow 2 n = 2 log x = log x^{2}$
Or $log x^{2} = 2 log x = 2 n$ .

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