Question

If $m=\frac{7x-3}{2.5}$, $n=\frac{32-2x}{1.6}$ and $m:n=4:3$, find the value of $x$.

• A. $6\frac{16}{67}$
• B. $6\frac{13}{67}$
• C. $6\frac{17}{67}$
• D. $6\frac{19}{67}$

Answer 1

The correct option is A $6\frac{16}{67}$

Given, $m=\frac{7x-3}{2.5},n=\frac{32-2x}{1.6}$ and $m:n=4:3$

Therefore, $\frac{\frac{7x-3}{2.5}}{\frac{32-2x}{1.6}}=\frac{4}{3}$

$\Rightarrow \frac{4(7x-3)}{25(32-2x)}=\frac{1}{3}$

$\Rightarrow \frac{28x-12}{800-50x}=\frac{1}{3}$

$\Rightarrow 84x-36=800-50x$

$\Rightarrow 134x=836$

$\Rightarrow x=\frac{836}{134}=6\frac{16}{67}$