If M-x1-x2-20-20 then the value of - 20i-1 xi-M -20 is

The correct option is C 0Given #160; M=x_1+x_2+20/20 #160; ⇒ x_1+x_2+20=20M Then #160; ∑_i=1^20 ( x_1 M/20 )=x_1+x_2+20 M/20=20M M/20=19M/20 ...

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Chain Rule of Differentiation

If M=x1+x2+...

Question

If $M = \frac{x_{1} + x_{2} +_{20}}{20}$ then the value of $20 \sum i = 1 \frac{(x_{i} - M)}{20}$ is

\frac{19 M}{20}

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1/20

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Similar questions

\frac{x_{1} + x_{2} + . . . + x_{20}}{20}

\sum_{i - 1}^{20} \frac{(x_{i} - M)}{20}

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Σ_{i = l}^{20} \frac{(x_{i} - m)}{20} i s

\frac{x_{1} + x_{2} . . . . + x_{20}}{20} = M

20 \sum i = 1 \frac{x_{i} - M}{20}

z = \frac{x^{1 / 25} - y^{1 / 25}}{x^{1 / 20} + y^{1 / 20}}

x \frac{\partial z}{\partial x} + y \frac{\partial z}{\partial y}

[\begin{matrix} x & 1 y & 2 \end{matrix}]

- [\begin{matrix} y & 1 8 & 0 \end{matrix}] =

[\begin{matrix} 2 & 0 - x & 2 \end{matrix}],

x

y

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