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Properties of Iota

If n 2 = n+...

Question

If $n^{2} = (n + 6)$ , then find the value of $n .$

n = - 2, - 3

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n = 3, 2

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n = - 3, 2

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n = - 2, 3

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Solution

The correct option is A $n = - 2, 3$
$n^{2} = (n + 6)$
$\Rightarrow n^{2} - n - 6 = 0$
$\Rightarrow (n - 3) (n + 2) = 0$
$\Rightarrow n = - 2, 3$

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