If n- 4- then tan- -tan 2- -tan 3- -tan 2n-1 - is equal to

The correct option is A 1 We have #160;tanα #160;tan( 2n 1 ) α #160; =tanα #160; .tan( π #160;/ 2α #160; 1 ) α #160; #160;=tanα # ...

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Properties Derived from Trigonometric Identities

If n=π/ 4α,...

Question

If $n = \frac{π}{4 α}$ , then $tan α . tan 2 α . tan 3 α . . . tan (2 n - 1) α$ is equal to

1

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Solution

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Similar questions

If $4 n α = π,$ then the numerical value of $tan α . tan 2 α . tan 3 α . . . . tan (2 n - 1) α$ is equal to

4 n α = π

tan α tan 2 α tan 3 α . . . tan (2 n - 1) α =

n = 1, 2, 3, . . ., then \cos α \cos 2 α \cos 4 α . . . \cos 2^{n - 1} α

\frac{\sin 2 n α}{2 n \sin α}

\frac{\sin 2^{n} α}{2^{n} \sin 2^{n - 1} α}

\frac{\sin 4^{n - 1} α}{4^{n - 1} \sin α}

\frac{\sin 2^{n} α}{2^{n} \sin α}

\tan^{- 1} (\tan \frac{5 π}{4}) and β = \tan^{- 1} (- \tan \frac{2 π}{3})

\frac{7 π}{12}

θ = \frac{π}{4 n}

tan θ tan 2 θ . . . tan (2 n - 1) θ

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