If n P- Q -0 then nP can possibly be

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Number of Elements in a Cartesian Product

If n P× Q =...

Question

If $n (P \times Q) = 0$ then n(P) can possibly be

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n (P) = 25

n (P \cap Q) = 5

n (P - Q)

n (P \times Q) = 200

P

Q, n (P) = 5, n (Q) = 4

n (P \times Q) =

nP4=20(nP2) then find the value of n

P = {x \in N : \frac{14 x}{x + 1} - (\frac{9 x - 30}{x - 4}) \leq 0},

Q = {x \in Z : | x - 1 | \leq 5 and | x - 1 | \geq 2}

R = {x \in R : {log}_{6} x + \frac{2}{{log}_{6} x}} = 3,

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