If nU-700-nA- 200-nB- 240-nA- B- 100- then nA- B- is equal to

The correct option is D 600 Using De Morgan's law, n(A'∪ B')= n(A∩ #160; B)' = n(U) n(A∩ B)= #160; n(U) 100 = 700 100= 600 ...

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If nU=700,n...

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If $n (U) = 700, n (A) = 200, n (B) = 240, n (A \cap B) = 100,$ then $n (A^{'} \cup B^{'})$ is equal to

260

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560

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360

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600

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Similar questions

n (U) = 700

n (A) = 200

n (B) = 300

n (A \cap B) = 100

n (A^{^{'}} \cap B^{^{'}})

If $n (U) = 700, n (A) = 200, n (B) = 300$ and $n (A \cap B) = 100,$ then $n (A^{'} \cap B^{'}) =$ ___.

n (u) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100, n (A^{'} \cap B^{'}) =

If $n (\cup)$ = 700, n(A) = 200, n(B) = 300 , $n (A \cap B)$ = 100, then $n (A^{^{'}} \cap B^{^{'}})$ = 300

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