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Question


If ω1is a cube root of unity, then value of the expression (1+2ω+2ω2)10+(2+ω+2ω2)10+(2+2ω+ω2)10 is equal to

A
3
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B
2
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C
1
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D
0
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Solution

The correct option is D 0
(1+2ω+2ω2)10+(2+ω+2ω2)10+(2+2ω+ω2)10

=(1)10+(ω)10+(ω2)10

=1+ω10+ω20

=1+ω+ω2

=0

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