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Question

If a,b,c are three vectors such that a=c=1,b=4,b×c=2 and 2b=c+λa then λ is

A
6583
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B
17
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C
3
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D
172(2+3)
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Solution

The correct option is A 6583
b×c=bcsinθ,θ being the angle between b and c.
2=4sinθ
θ=π6
Now, we have λa=2bc
λ|a|=4|b|2+|c|24bc
λ2=64+183
λ=6583

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