If u- v- w are three noncoplanar vectors then - u-v-w u-v v- w -equals

The correct option is A [ u v w ] We have #160; [ u+v w u v v #160;w #160; ] #160; = [u v w] × 1 amp; 1 amp; 1 1 a ...

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Dot Product

If u, v, w ...

Question

If $\to u, \to v, \to w$ are three noncoplanar vectors then $[\to u + \to v - \to w \to u - \to v \to v - \to w]$ equals

[\to u \to v \to w]

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[\to u \to w \to v]

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3 [\to u \to v \to w]

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0

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Solution

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u, v

w

u + v + w = 0

| u | = 3, | v | = 4

| w | = 5

u . v + v . w + w . u

\vec{u,} \vec{v} and \vec{w}

\vec{u} + \vec{v} + \vec{w} = \vec{0} .

|\vec{u}| = 3, |\vec{v}| = 4 and |\vec{w}| = 5,

\vec{u} \cdot \vec{v} + \vec{v} \cdot \vec{w} + \vec{w} \cdot \vec{u} .

P (3 u^{2}, 2 u^{3}); Q (3 v^{2}, 2 v^{3}); R (3 w^{2}, 2 w^{3})

u v + v w + w u

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