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Question

If P be the sum of odd term and Q that of even terms in the expansion of (x+a)n , then the value of [(x+a)2n−(x−a)2n] equals

A
PQ
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B
2PQ
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C
4PQ
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D
None of these
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Solution

The correct option is C 4PQ
P=(x+a)n+(xa)n2 ...(i)
Q=(x+a)n(xa)n2 ...(ii)
Hence, 2P.2Q
=4PQ
=[(x+a)n+(xa)n][(x+a)n(xa)n]
=(x+a)2n(xa)2n

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