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Question

If p=b×c[abc],q=c×a[abc],r=a×b[abc] where a,b,c are three non-coplanar vectors then the value of the expression (a+b+c).(p+q+r) is

A
3
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B
2
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C
1
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D
0
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Solution

The correct option is D 3
a.p=a.(b×c)[abc]=[abc][abc]=1=b.q=c.r
b.p=b.(b×c)[abc]=0[abc]=0=c.q=a.r
Therefore , the given expression is equal to
(a+b+c).(p+q+r)=1+0+1+0+1+0=3

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