Question

If $p=\frac{w}{2g}(v^2-u^2)$ then the value of P when $w=40,g=32,u=4,v=12$ is

• A. $80$
• B. $82$
• C. $90$
• D. $78$

Answer 1

The correct option is A $80$

Given equation is: $\frac{w}{2g}(v^2-u^2)$

Also given, $w=40,g=32,u=4,v=12$

$p=\frac{40}{2\times 32}({12}^2-4^2)$

$=\frac{40}{64}(144-16)$

$=\frac{40}{64}\left(128\right)$

$=40\left(2\right)$
$=80$
Option A is correct.