If P(at2,2at) be one end of a focal chord of the parabola y2=4ax, then the length of the chord is
A
a(t−1t)2
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B
a(t−1t)
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C
a(t+1t)
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D
a(t+1t)2
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Solution
The correct option is Da(t+1t)2 If P(at2,2at) be one end of a focal chord of the parabola y2=4ax, then another end of chord will be Q(at2,−2at). ∴ Length of focal chord = PQ =√(at2−at2)2+(−2at−2at)2 =a√(1t−t)2(1t+t)2+4(1t+t)2 =a(1t+t)√(1t−t)2+4 =a(1t+t)2